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4.2 Change in Momentum and Impulse

Part of Linear Momentum in AP® Physics 1: Algebra-Based. Read the opening section, then create a free account for the full interactive lesson, practice, and progress tracking.

Impulse

Forces play a key role in changing or transferring momentum, and they do this through a concept called impulse. Impulse connects force and momentum directly, helping us understand how applying a force over time changes an object’s motion. Impulses cause an object’s momentum to change. Impulse is a vector, measured in kilograms - meters per second, and represented with either the variable J{J} or p{p}. The direction of the impulse vector on an object is in the same direction as the net force exerted on the object.

Δp=FavgΔt\Delta p=F_{avg} \Delta t
p represents the change in momentum of an object due to the impulse Favg is the average force exerted on an object t is the time interval over which the force was exerted over

This equation can actually be used to derive Newton’s 2nd Law. By solving for the force, you get Favg=ΔpΔt{F_{avg}=\frac{\Delta p}{\Delta t}}. Assuming mass is constant, Δp{\Delta p} is just mΔv{m \Delta v}, making the equation Favg=mΔvΔt{F_{avg}=\frac{m \Delta v}{\Delta t}}. By definition ΔvΔt=a{\frac{\Delta v}{\Delta t}=a}, and also, the average force at an instant is just the net force on a system, so you get the equation Fnet=ma{F_{net}=ma}.

The change in momentum of an object is just an object’s final momentum minus its initial momentum.
Δp=p−po\Delta p=p-p_o
  • Δp{\Delta p} represents the change in momentum of an object
  • p{p} is the final momentum of the object
  • po{p_o} is the initial momentum of the object
MCQ Reading Checkpoint

Which has the highest net force being exerted on it, assuming all of the collisions/interactions take the same amount of time?

Choose the best option:

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