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9.3 Conservation of Electric Energy

Part of Electric Potential in AP® Physics C: Electricity and Magnetism. Read the opening section, then create a free account for the full interactive lesson, practice, and progress tracking.

2.3 Conservation of Electrical Energy

We can solve a whole class of problems by using the fact that electrical energy + kinetic energy is conserved by conservation of energy.

An electron of charge −e{-e} is accelerated through a potential difference of ΔV=5V{\Delta V = 5V}. If it is initially at rest, what is the final speed v{v} the electron reaches after moving through the potential difference? \

At the start prior to motion, the electron would have potential energy. This potential energy is converted to kinetic energy as the electron traverses the potential difference.

∣ΔU∣=eΔV=∣ΔKE∣=12mv2|\Delta U| = e\Delta V = |\Delta KE| = \frac{1}{2}mv^2

Solving for v{v} gives us →v=2eΔVm{\rightarrow v = \sqrt{\frac{2e\Delta V}{m}}}. Using the known quantities of e=1.6⋅10−19 C{e = 1.6 \cdot 10^{-19} \text{ C}} and m=9.11⋅10−31 kg{m = 9.11 \cdot 10^{-31} \text{ kg}} gives us v=1.3⋅106 m/s{v = 1.3 \cdot 10^6 \text{ m/s}}.

This is the whole idea of these problems. We simply note when energy is conserved and apply conservation of energy, relating potential energy to charge multiplied by potential difference and setting it equal to change in kinetic energy.

In this unit

3 lessons

  1. 9.1Electric Potential EnergyPreview lesson
  2. 9.2Electric PotentialPreview lesson
  3. 9.3Conservation of Electric EnergyThis lesson

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