Back to Electric Circuits

Lesson PreviewLesson 8 of 8 in this unit

11.8 Resistor Capacitor (RC) Circuits

Part of Electric Circuits in AP® Physics C: Electricity and Magnetism. Read the opening section, then create a free account for the full interactive lesson, practice, and progress tracking.

An RC circuit contains a resistor and capacitor and exhibits time-dependent behavior. When a capacitor charges through a resistor from a battery E{\mathcal{E}}, the current is initially largest and then decays to zero as the capacitor fills. During charging, the loop equation is

E−IR−qC=0\mathcal{E} - IR - \frac{q}{C} = 0

Since I=dq/dt{I = dq/dt}, this becomes the differential equation

Rdqdt+qC=ER\frac{dq}{dt} + \frac{q}{C} = \mathcal{E}

whose solution is

q(t)=CE(1−e−t/RC)q(t) = C\mathcal{E}\left(1 - e^{-t/RC}\right)

and therefore

I(t)=ERe−t/RCI(t) = \frac{\mathcal{E}}{R} e^{-t/RC}

The combination τ=RC{\tau = RC} is the time constant.

For discharging, the battery is removed and the loop equation becomes

IR+qC=0IR + \frac{q}{C} = 0

or

Rdqdt+qC=0R\frac{dq}{dt} + \frac{q}{C} = 0

with solution

q(t)=Q0e−t/RCq(t) = Q_0 e^{-t/RC}

and

I(t)=−Q0RCe−t/RCI(t) = -\frac{Q_0}{RC} e^{-t/RC}

The minus sign indicates discharge direction opposite the charging direction convention. These are among the most calculus-heavy equations in the circuits unit because they come from solving first-order differential equations.

Continue the full lesson in Stellar

Create a free account to unlock the remaining sections, checkpoints, course practice, and progress tracking for AP® Physics C: Electricity and Magnetism.