You should think of parametric differentiation as a chain-rule idea: since both coordinates depend on t, the derivative with respect to x comes from comparing the two rates. If is positive and is also positive, then the slope is positive. If they have opposite signs, the slope is negative. Parametric equations can trace curves in ways ordinary y=f(x) equations cannot, such as loops or paths that double back, which is why this representation is so important in BC calculus.
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9.1 Defining and Differentiating Parametric Equations
Part of Parametric Equations, Polar Coordinates, and Vector-Valued Functions in AP® Calculus BC. Read the opening section, then create a free account for the full interactive lesson, practice, and progress tracking.
A parametric equation describes both x and y in terms of a third variable, usually t. Instead of writing y directly as a function of x, you write x=f(t) and y=g(t). This is useful when motion or geometry is easier to describe through a parameter, such as time. To find the slope of the curve, you use
as long as . This tells you how fast y changes compared to x, even though both are changing with respect to t.
In this unit
9 lessons
- 9.1Defining and Differentiating Parametric EquationsThis lesson
- 9.2Second Derivatives of Parametric EquationsPreview lesson
- 9.3Finding Arc Lengths of Curves Given by Parametric EquationsPreview lesson
- 9.4Defining and Differentiating Vector-Valued FunctionsPreview lesson
- 9.5Integrating Vector-Valued FunctionsPreview lesson
- 9.6Solving Motion Problems Using Parametric and Vector-Valued FunctionsPreview lesson
- 9.7Defining Polar Coordinates and Differentiating in Polar FormPreview lesson
- 9.8Find the Area of a Polar Region or the Area Bounded by a Single Polar CurvePreview lesson
- 9.9Finding the Area of the Region Bounded by Two Polar CurvesPreview lesson
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