You should think of polar differentiation as a parametric problem in disguise. Once x and y are rewritten in terms of , the same derivative machinery from parametric equations applies. Polar graphs can create roses, limacons, and spirals, so this system describes curves that are often awkward in rectangular form. The main challenge is converting correctly and differentiating carefully.
Back to Parametric Equations, Polar Coordinates, and Vector-Valued Functions
Lesson PreviewLesson 7 of 9 in this unit
9.7 Defining Polar Coordinates and Differentiating in Polar Form
Part of Parametric Equations, Polar Coordinates, and Vector-Valued Functions in AP® Calculus BC. Read the opening section, then create a free account for the full interactive lesson, practice, and progress tracking.
In polar coordinates, a point is described by (r,θ) instead of (x,y). Here r is the distance from the origin and θ is the angle from the positive x-axis. The rectangular and polar systems are connected by
and
If r is given as a function of θ, then you can differentiate parametrically by treating θ as the parameter. The slope formula is
provided
In this unit
9 lessons
- 9.1Defining and Differentiating Parametric EquationsPreview lesson
- 9.2Second Derivatives of Parametric EquationsPreview lesson
- 9.3Finding Arc Lengths of Curves Given by Parametric EquationsPreview lesson
- 9.4Defining and Differentiating Vector-Valued FunctionsPreview lesson
- 9.5Integrating Vector-Valued FunctionsPreview lesson
- 9.6Solving Motion Problems Using Parametric and Vector-Valued FunctionsPreview lesson
- 9.7Defining Polar Coordinates and Differentiating in Polar FormThis lesson
- 9.8Find the Area of a Polar Region or the Area Bounded by a Single Polar CurvePreview lesson
- 9.9Finding the Area of the Region Bounded by Two Polar CurvesPreview lesson
Continue the full lesson in Stellar
Create a free account to unlock the remaining sections, checkpoints, course practice, and progress tracking for AP® Calculus BC.