6.11 Carrying Out a Test for the Difference of Two Population Proportions

Finding the p-Value and Concluding

Continuing from the example in Lesson 6.10:

${z = -1.50}$, ${H_a: p_1 \neq p_2}$ (two-sided)

Decision (at ${\alpha = 0.05}$): ${0.1336 > 0.05}$ → Fail to reject ${H_0}$

Conclusion: Since the ${p}$-value ${(0.1336)}$ is greater than ${\alpha = 0.05}$, we fail to reject ${H_0}$. We do not have convincing evidence that male and female students use tutoring services at different rates.