Back to Probability, Random Variables, and Probability Distributions

Lesson PreviewLesson 5 of 12 in this unit

4.5 Conditional Probability

Part of Probability, Random Variables, and Probability Distributions in AP® Statistics. Read the opening section, then create a free account for the full interactive lesson, practice, and progress tracking.

Conditional Probability

Conditional probability B)|

P(A∣B)=P(A∩B)P(B)(provided P(B)>0)P(A \mid B) = \frac{P(A \cap B)}{P(B)} \quad \text{(provided } P(B) > 0\text{)}

Interpretation: "Given that B occurred, what is the probability of A?"

Example (Two-way table):

Has Disease No Disease Total
Test Positive 45 5 50
Test Negative 10 940 950
Total 55 945 1000

P(Disease∣Positive Test)=4550=0.90{P(\text{Disease} \mid \text{Positive Test}) = \frac{45}{50} = 0.90} — given a positive test, 90% chance of having disease

P(Positive Test∣No Disease)=5945≈0.0053{P(\text{Positive Test} \mid \text{No Disease}) = \frac{5}{945} \approx 0.0053} — false positive rate

Note: P(A∣B)≠P(B∣A){P(A \mid B) \neq P(B \mid A)} in general!

Continue the full lesson in Stellar

Create a free account to unlock the remaining sections, checkpoints, course practice, and progress tracking for AP® Statistics.